A proton and an electron have the same de Broglie wavelength. If $$K_p$$ and $$K_e$$ be the kinetic energies of proton and electron respectively, then choose the correct relation :

$$ p = \frac{h}{\lambda} $$

Since both have the same de Broglie wavelength, they both will have the same momentum.

$$ KE = \frac{p^2}{2m} $$

$$KE$$ is inversely proportional to $$m$$.

$$ m_p > m_e $$

$$ K_p < K_e $$

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