If the number of projects handled by company A increased by 20% from 2007 to 2008 and by 5% from 2008 to 2009, what was the number of projects handled by company A in 2009?

Solution

Number of projects handled by company A in 2007 = 190

=> Number of projects handled by company A in 2008 = $$190 + \frac{20}{100} \times 190$$

= $$190 + 38 = 228$$

$$\therefore$$ Number of projects handled by company A in 2009 = $$228 + \frac{5}{100} \times 228$$

= $$228 + 11.4 = 239.4$$

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