Study the information carefully to answer the following questions:
A bucket contains 8 red, 3 blue and 5 green marbles.
If 2 marbles are drawn at random, what is the probability that both are green?
Number of ways of drawing 2 marbles out of 16
$$n(S) = C^{16}_2 = \frac{16 \times 15}{1 \times 2}$$
= $$120$$
Out of the two drawn marbles, both are green
=> $$n(E) = C^5_2 = \frac{5 \times 4}{1 \times 2}$$
= $$10$$
$$\therefore$$ Required probability = $$\frac{n(E)}{n(S)}$$
= $$\frac{10}{120} = \frac{1}{12}$$
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