A and B together can complete a particular task in 8 days. If B alone can complete the same task in 10 days, how many days will A take to complete the task if he works alone?
Let the total work to be done = 40 units
Rate at which B alone finishes the task = $$\frac{40}{10}$$ = 4 units/day
Rate at which A & B together finishes the work = $$\frac{40}{8}$$ = 5 units/day
=> Rate at which A alone finishes the work = 5 - 4 = 1 units/day
$$\therefore$$ Time taken by A to complete the task = $$\frac{40}{1}$$ = 40 days
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