Instructions

In each of these questions two equations numbered I and II are given. You have to solve both the equations and –
Give answer a: if x < y
Give answer b: if x ≤ y
Give answer c: if x > y
Give answer d: if x ≥ y
Give answer e: if x = y or the relationship cannot be established.

Question 150

I.$$x^{2}+12x+32=0$$
II. $$y^{2} +17y+72=0$$

Solution

I.$$x^{2} + 12x + 32 = 0$$

=> $$x^2 + 8x + 4x + 32 = 0$$

=> $$x (x + 8) + 4 (x + 8) = 0$$

=> $$(x + 8) (x + 4) = 0$$

=> $$x = -8 , -4$$

II.$$y^{2} + 17y + 72 = 0$$

=> $$y^2 + 9y + 8y + 72 = 0$$

=> $$y (y + 9) + 8 (y + 9) = 0$$

=> $$(y + 9) (y + 8) = 0$$

=> $$y = -9 , -8$$

$$\therefore x \geq y$$


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