Is the slope of the straight line equal to $$\frac{3}{5}$$ ?
I. The straight line is passing through the point (3,5)
II. The straight line perpendicular to 5x - 3y + 4 = 0

To find the slope, you divide the difference of the y-coordinates of 2 points on 

a line by the difference of the x-coordinates of those same 2 points.

In statement I no coordinates are given for line.

II.

$$5x-3y+4=0.$$

or,$$5x+4=3y.$$

or,$$\ \frac{\ 5}{3}x+\frac{\ 4}{3}=y.$$

The slope of the line perpendicular to this one will have a slope equal to the negative reciprocal.

The perpendicular slope is $$-\ \frac{\ 3}{5}.$$

Plug the new slope and the given point into the slope-intercept form to find the y-intercept.

$$5=-\ \frac{\ 3}{5}\times3+b$$

or,$$\ \frac{\ 34}{5}=b$$.

$$y=-\ \frac{\ 3}{5}x+\frac{\ 34}{5}.$$

So, Option B is correct choice.