Question 148

A project requires 12 women to complete it in 16 days. 12 women started working and after a few days from the start of the project, 4 women left. If the remaining project was completed in 18 days, in how many days the whole project was completed?

Solution

Let the work done by 8 women in 18 days = $$W_2$$

=> $$\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$$

=> $$\frac{12 \times 16}{1} = \frac{8 \times 18}{W_2}$$

=> $$W_2 = \frac{18}{12 \times 2} = \frac{3}{4}$$

Thus, remaining work = $$1 - \frac{3}{4} = \frac{1}{4}$$

This part of work was done by 12 women.

$$\therefore$$ Time taken by them = 4 days

=> Required time = 18 + 4 = 22 days

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