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Instructions
In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ y
Give answer c: if x < y
Give answer d: if x ≤ y
Give answer e: if x = y or the relationship cannot be established.
Solution
I.$$2x^{2} + 21x + 10 = 0$$
=> $$2x^2 + x + 20x + 10 = 0$$
=> $$x (2x + 1) + 10 (2x + 1) = 0$$
=> $$(x + 10) (2x + 1) = 0$$
=> $$x = -10 , \frac{-1}{2}$$
II.$$3y^{2} + 13y + 14 = 0$$
=> $$3y^2 + 6y + 7y + 14 = 0$$
=> $$3y (y + 2) + 7 (y + 2) = 0$$
=> $$(y + 2) (3y + 7) = 0$$
=> $$y = -2 , \frac{-7}{3}$$
$$\therefore$$ No relation can be established.
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