Question 145

Standard deviation of any five consecutive integers is

Solution

As, any five consecutive integers are required, for the sake of easy calculation take the integers as 1,2,3,4,5

Standard deviation , Sigma = $$\sqrt{\ }$$[(x - x bar ) ^ 2]/N

x     Deviation

1      (1-3)^2=4

2      (2-3)^2=1

3      (3-3)^2=0

4      (4-3)^2=1 

5      (5-3)^2=4

      where xbar = 3 (assumed mean)

Sum of X bar = 4+1+0+1+4 = 10

Therefore, $$\sigma\ $$ = $$\sqrt{\ }$$(10/5)

                   = $$\sqrt{\ }$$2    Ans.


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