Question 145

Standard deviation of any five consecutive integers is

As, any five consecutive integers are required, for the sake of easy calculation take the integers as 1,2,3,4,5

Standard deviation , Sigma =Β $$\sqrt{\ }$$[(x - x bar ) ^ 2]/N

xΒ  Β  Β Deviation

1Β  Β  Β  (1-3)^2=4

2Β  Β  Β Β (2-3)^2=1

3Β  Β  Β Β (3-3)^2=0

4Β  Β  Β  (4-3)^2=1Β 

5Β  Β  Β Β (5-3)^2=4

Β  Β  Β  where xbar = 3 (assumed mean)

Sum of X bar = 4+1+0+1+4 = 10

Therefore,Β $$\sigma\ $$ =Β $$\sqrt{\ }$$(10/5)

Β  Β  Β  Β  Β  Β  Β  Β  Β  Β =Β $$\sqrt{\ }$$2Β  Β  Ans.

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