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As, any five consecutive integers are required, for the sake of easy calculation take the integers as 1,2,3,4,5
Standard deviation , Sigma =Β $$\sqrt{\ }$$[(x - x bar ) ^ 2]/N
xΒ Β Β Deviation
1Β Β Β (1-3)^2=4
2Β Β Β Β (2-3)^2=1
3Β Β Β Β (3-3)^2=0
4Β Β Β (4-3)^2=1Β
5Β Β Β Β (5-3)^2=4
Β Β Β where xbar = 3 (assumed mean)
Sum of X bar = 4+1+0+1+4 = 10
Therefore,Β $$\sigma\ $$ =Β $$\sqrt{\ }$$(10/5)
Β Β Β Β Β Β Β Β Β Β =Β $$\sqrt{\ }$$2Β Β Ans.
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