Question 144

In the electrochemical cell
$$Zn \mid ZnSO_4 (0.01M)\parallel CuSO 4 (1.0 M)\mid Cu$$, the emf of this Daniel cell is $$E_1$$. When the concentration of $$ZnSO_4$$ is changed to 1.0 M and that of $$CuSO_4$$ changed to 0.01 M, the emf changes to $$E_2$$. From the following, which one is the relationship between $$E_1 and E_2$$ ?
(Given, $$\frac{RT}{F} = 0.059$$)


Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free

cracku

Boost your Prep!

Download App