In a series LCR circuit, the inductive reactance $$(X_L)$$ is 10 $$\Omega$$ and the capacitive reactance $$(X_C)$$ is 4 $$\Omega$$. The resistance $$(R)$$ in the circuit is 6 $$\Omega$$. The power factor of the circuit is :

In a series LCR circuit, the impedance is $$Z = \sqrt{R^2 + (X_L - X_C)^2}$$.

Substituting the given values: $$Z = \sqrt{6^2 + (10 - 4)^2} = \sqrt{36 + 36} = \sqrt{72} = 6\sqrt{2}$$ $$\Omega$$.

The power factor is $$\cos\phi = \frac{R}{Z} = \frac{6}{6\sqrt{2}} = \frac{1}{\sqrt{2}}$$.

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