For the given figures, choose the correct options:

Solution :

For circuit (a), only resistance is present.

Therefore,

$$I_a = \frac{V}{R}$$

$$= \frac{220}{40}$$

$$= 5.5\text{ A}$$

For circuit (b), impedance is :

$$Z = \sqrt{R^2+(X_L-X_C)^2}$$

Hence,

$$Z \ge R$$

Therefore,

$$I_b = \frac{V}{Z} \le \frac{V}{R}$$

Thus, rms current in circuit (b) can never be greater than that in (a).

At resonance,

$$X_L = X_C$$

So,

$$Z = R$$

Hence,

$$I_b = \frac{V}{R} = I_a$$

Therefore,

Statement 1 is correct.

Statement 2 is incorrect.

Statement 3 is incorrect.

Statement 4 is incorrect.

Final Answer :

Only Statement 1 is correct.