If $$2^{2n - 1} = \frac{1}{8^{n - 3}}$$, then the value of 'n' is:
Given that $$2^{2n - 1} = \frac{1}{8^{n - 3}}$$
=>Â $$2^{2n - 1} = 8^{3 - n}$$
=>Â $$2^{2n - 1} = 2^{9 - 3n}$$
As the bases are equal, their powers are equal
=> 2n-1 = 9-3n
=> 5n=10
=> n=2
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