Question 139

If $$2^{2n - 1} = \frac{1}{8^{n - 3}}$$, then the value of 'n' is:

Solution

Share

Given that $$2^{2n - 1} = \frac{1}{8^{n - 3}}$$

=>  $$2^{2n - 1} = 8^{3 - n}$$

=>  $$2^{2n - 1} = 2^{9 - 3n}$$

As the bases are equal, their powers are equal

=> 2n-1 = 9-3n

=> 5n=10

=> n=2

Create a FREE account and get:

  • Download RRB Study Material PDF
  • 45+ RRB previous papers with solutions PDF
  • 300+ Online RRB Tests for Free