Question 139
A person travels from P to Q at a speed of 40 kmph and returns to Q by increasing his speed by 50%. What is his average speed for both the trips?
Solution
Return speed = $$\frac{40}{100}$$ x 150 = 60 kmph
Average speed = $$\frac{2 \times 40 \times 60}{(40 + 60)}$$
$$\frac{4800}{100}$$ = 48kmph
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