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The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is
$$x^2 + y^2 = 9a^2$$
$$x^2 + y^2 = 16a^2$$
$$x^2 + y^2 = 4a^2$$
$$x^2 + y^2 = a^2$$
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