Question 135

The denominators of two fractions are 5 and 7 respectively. The sum of these fractions is 41/35 . On interchanging the numerators, their sum becomes 43/35 . The fractions are

Solution

Let the two fractions be $$\frac{x}{5}$$ and $$\frac{y}{7}$$

Acc to ques,

=> $$\frac{x}{5} + \frac{y}{7} = \frac{41}{35}$$

=> $$\frac{7x + 5y}{35} = \frac{41}{35}$$

=> $$7x + 5y = 41$$

After interchanging the numerators

=> $$\frac{y}{5} + \frac{x}{7} = \frac{43}{35}$$

=> $$\frac{5x + 7y}{35} = \frac{43}{35}$$

=> $$5x + 7y = 43$$

Solving above equations, we get :

=> $$x = 3 , y = 4$$

$$\therefore$$ Original fractions = $$\frac{3}{5} , \frac{4}{7}$$


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