Solution
$$=\frac{x^2 - \sqrt{x}}{\sqrt{x} - 1}$$
After differentiation:
$$\frac{2x - \frac{1}{2\sqrt{x}}}{\frac{1}{2\sqrt{x}}}$$
Now,
= $$\lim_{x \rightarrow 1}\frac{2x - \frac{1}{2\sqrt{x}}}{\frac{1}{2\sqrt{x}}}$$
= $$\frac{2 - \frac{1}{2}}{\frac{1}{2}}$$
= $$\frac{\frac{3}{2}}{\frac{1}{2}}$$
= $$3$$
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