Question 134

I.  $$ 2x^{2}-19x+45 =0 $$
II. $$ 6y^{2}-48y+90=0  $$

Solution

I.$$2x^{2} - 19x + 45 = 0$$

=> $$2x^2 - 10x - 9x + 45 = 0$$

=> $$2x (x - 5) - 9 (x - 5) = 0$$

=> $$(x - 5) (2x - 9) = 0$$

=> $$x = 5 , \frac{9}{2}$$

II.$$6y^{2} - 48y + 90 = 0$$

=> $$y^2 - 8y + 15 = 0$$

=> $$y^2 - 3y - 5y + 15 = 0$$

=> $$y (y - 3) - 5 (y - 3) = 0$$

=> $$(y - 3) (y - 5) = 0$$

=> $$y = 3 , 5$$

Hence no relation can be established.


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