Question 131
The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle ?
Solution
Let the base of rectangle be y , then its length will be = y+6
perimeter of triangle = 84
2(length + breadth) = 84
2(2y + 6) = 84
2y + 6 = 42
y = 18 m
length of rectangle = height of triangle = 18 + 6 = 24 m
Diagonal of rectangle = base of Triangle = $$\sqrt{(24)^2 + (18)^2}$$ = 30
Area of Triangle = $$\frac{1}{2}\times30\times24$$
Area of Triangle = 360 sq m
Get AI Help
Create a FREE account and get:
- Banking Quant Shortcuts PDF
- Free Banking Study Material - (15000 Questions)
- 135+ Banking previous papers with solutions PDF
- 100+ Online Tests for Free
