Question 131

The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle ?

Solution

Let the base of rectangle be y , then its length will be = y+6

perimeter of triangle = 84

2(length + breadth) = 84

2(2y + 6) = 84

2y + 6 = 42

y = 18 m

length of rectangle = height of triangle = 18 + 6 = 24 m

Diagonal of rectangle = base of Triangle = $$\sqrt{(24)^2 + (18)^2}$$ = 30

Area of Triangle = $$\frac{1}{2}\times30\times24$$

Area of Triangle = 360 sq m

Create a FREE account and get: