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Nine friends – P. Q, R, S, T, U, V. W and X — live on nine different floors of a building but not necessarily in the same order. The lower most floor of the building is numbered one, the one above that is numbered two and so on till the topmost floor is numbered nine. T lives on an odd numbered floor below the floor numbered five. Only three people live between T and X. Only one person lives between X and V. V lives above X. Q lives on an odd numbered floor immediately below P. Q lives on the floor numbered five. The number of persons living between X and P is equal to the number of people living between T and S. W lives on an even numbered floor immediately above R.
Four of the following five are alike in a certain way as per the given arrangement and thus form a group. Which of the following does not belong to that group?
Q lives on fifth floor, => P lives on 6th floor.
T lives on an odd numbered floor below the floor numbered five and only three people live between T and X,
=> If T lives on 1st floor, then X must lives on fifth floor which is not possible as Q is living on it.
=> T lives on 3rd floor and X on 7th floor.
Only one person lives between X and V and V lives above X, => V lives on 9th floor.
Since, there is no one living between X and P, => no one must also live between T and S, thus S lives on 4th floor.
W lives on an even numbered floor immediately above R, => W lives on 2nd floor and R lives on 1st floor.
=> U lives on 8th floor. The arrangement is :
The number of persons living between X and T are 3, i.e. odd , whereas the number of persons living between rest all the pairs are even.
=> Ans - (C)
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