To complete a project, 18 women take 4 more days than the number of days taken by 12 men. If eight men complete the project in 9 days, how much work will be left when 15 women and 12 men together work for 3 days ?

Using : $$\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$$

Acc to ques,

=> $$\frac{8 \times 9}{1} = \frac{12 \times D_2}{1}$$

=> $$D_2 = \frac{72}{12} = 6$$

=> Time taken by 18 women = $$6 + 4 = 10$$ days

=> $$(12 \times 6) men \equiv (18 \times 10) women$$

= $$2 men \equiv 5 women$$

We need to find for 15 women and 12 men

= $$(6 + 12) = 18 men$$

Acc to ques,

=> $$\frac{12 \times 6}{1} = \frac{18 \times 3}{W_2}$$

=> $$W_2 = \frac{54}{72} = \frac{3}{4}$$

$$\therefore$$ Work left = $$1 - \frac{3}{4}$$

= $$\frac{1}{4}$$