Instructions

In each question, two equations numbered I and II are given.

You have to solve both the equations and mark an appropriate answer.
Give answer :

a: If x ≤ y
b: If x > y
c: If relationship between x and y cannot be established
d: x < y
e: x ≥ y

Question 128

I. $$2x^{2} + 7x + 6 = 0$$
II. $$2y^{2} + 17y + 30 =0$$

Solution

I. $$2x^{2} + 7x + 6 = 0$$

=> $$2x^2 + 4x + 3x + 6 = 0$$

=> $$2x (x + 2) + 3 (x + 2) = 0$$

=> $$(2x + 3) (x + 2) = 0$$

=> $$x = -2 , \frac{- 2}{3}$$

II. $$2y^{2} + 17y + 30 = 0$$

=> $$2y^2 + 12y + 5y + 30 = 0$$

=> $$2y (y + 6) + 5 (y + 6) = 0$$

=> $$(2y + 5) (y + 6) = 0$$

=> $$y = -6 , \frac{- 5}{2}$$

$$\therefore x > y$$

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I. $$2x^{2} + 7x + 6 = 0$$II. $$2y^{2} + 17y + 30 =0$$