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Set X contains 10 consecutive integers. Sum of the 5 least numbers of the set is 265. The sum of the four greatest numbers of that set is
10 consecutive integers are:-
$$Β x,(x+1),(x+2), (x+3), (x+4),--------(x+9)$$
sum of the 5 least number of the set is 265
Β Β $$\RightarrowΒ x+(x+1)+(x+2)+(x+3)+(x+4) = 265$$
Β Β $$\RightarrowΒ 5x+10 = 265$$
Β $$\RightarrowΒ 5x = 255$$
Β $$\RightarrowΒ x = \dfrac{255}{5}$$
Β $$\RightarrowΒ x = 51$$
Therefore, the sum of 4 greatest number of the set will be
Β $$\Rightarrow (x+6)+(x+7)+(x+8)+(x+9)$$
Β $$\RightarrowΒ 4x+30$$
Β $$\RightarrowΒ 4\times 51+30$$Β
Β $$\Rightarrow 204+30$$
Β Β Hence the sun of the greatest number will beΒ Β 234
Β
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