Question 127

Set X contains 10 consecutive integers. Sum of the 5 least numbers of the set is 265. The sum of the four greatest numbers of that set is

10 consecutive integers are:-

$$Β x,(x+1),(x+2), (x+3), (x+4),--------(x+9)$$

sum of the 5 least number of the set is 265

Β Β  $$\RightarrowΒ x+(x+1)+(x+2)+(x+3)+(x+4) = 265$$

Β  Β $$\RightarrowΒ 5x+10 = 265$$

Β  $$\RightarrowΒ 5x = 255$$

Β  $$\RightarrowΒ x = \dfrac{255}{5}$$

Β  $$\RightarrowΒ x = 51$$

Therefore, the sum of 4 greatest number of the set will be

Β  $$\Rightarrow (x+6)+(x+7)+(x+8)+(x+9)$$

Β  $$\RightarrowΒ 4x+30$$

Β $$\RightarrowΒ 4\times 51+30$$Β 

Β  $$\Rightarrow 204+30$$

Β  Β Hence the sun of the greatest number will beΒ Β 234

Β 

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