Question 124

The area of an equilateral triangle is $$24\sqrt{3} cm^2$$. What is the perimeter of this equilateral triangle ?

Given , area of triangle = $$24\sqrt{3} cm^2$$

$$\frac{\sqrt{3}}{4} a^2 = 24\sqrt{3} cm^2$$

a = $$4\sqrt{6} cm^2$$

Perimeter = 3 ($$4\sqrt{6}$$) = $$12\sqrt{6}$$

So, the answer would be option c)$$12\sqrt{6}$$ cm

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