Question 124
The area of an equilateral triangle is $$24\sqrt{3} cm^2$$. What is the perimeter of this equilateral triangle ?
Solution
Given , area of triangle = $$24\sqrt{3} cm^2$$
$$\frac{\sqrt{3}}{4} a^2 = 24\sqrt{3} cm^2$$
a = $$4\sqrt{6} cm^2$$
Perimeter = 3 ($$4\sqrt{6}$$) = $$12\sqrt{6}$$
So, the answer would be option c)$$12\sqrt{6}$$ cm
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