If two of the factors of the polynomial $$x^3 + x^2 - 10x + 8$$ and x - 1 and x - 2 then the third factors is
If x+a is factor of a polynomial f(x), then f(-a) should be zero
f(-4) = $$\left(-4\right)^3+\left(-4\right)^2-10\left(-4\right)+8=0$$
Hence x+4 is the third factor.
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