Instructions

In each question, two equations numbered I and II are given.

You have to solve both the equations and mark an appropriate answer.
Give answer :

a: If x ≤ y
b: If x > y
c: If relationship between x and y cannot be established
d: x < y
e: x ≥ y

Question 124

I. $$x^{2} = 10 $$
if $$y^{2} - 9y+ 20=0 $$

Solution

I. $$x^2 = 10$$

=> $$x = \pm \sqrt{10}$$

II. $$y^{2} - 9y + 20 = 0$$

=> $$y^2 - 4y - 5y + 20 = 0$$

=> $$y (y - 4) - 5 (y - 4) = 0$$

=> $$(y - 5) (y - 4) = 0$$

=> $$y = 4 , 5$$

$$\therefore x < y$$

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I. $$x^{2} = 10 $$if $$y^{2} - 9y+ 20=0 $$