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Instructions
In the following questions three equations numbered I, II and III are given.
You have to solve all the equations either together or separately, or two together and one
separately, or by any other method and Give answer
a: x< y=z
b: x ≤ y < z
c: x < y > z
d: x = y > z
e: x = y = z or if none of the above relationship is established
Solution
From I : $$(x+ y)^{3} = 1331$$
=> $$(x + y) = \sqrt[3]{1331} = 11$$
=> $$y = 11 - x$$
From III : $$xy = 28$$
=> $$x (11 - x) = 28$$
=> $$x^2 - 11x + 28 = 0$$
=> $$x^2 - 7x - 4x + 28 = 0$$
=> $$x (x - 7) - 4 (x - 7) = 0$$
=> $$(x - 7) (x - 4) = 0$$
=> $$x = 4 , 7$$
From equation I, => $$y = 7 , 4$$
Now, from II : $$z = y - x$$
=> $$z = 3 , -3$$
$$\therefore$$ No relation can be established.
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