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Twelve people are sitting in two parallel rows containing six people each such that they are equidistant from each other. In row 1: P, Q, R, S, T and V are seated and all of them are facing South. In row 2: A, B, C, D, E and F are seated and all of them are facing North. Therefore in the given seating arrangement, each member is seated in a row faces another member of the other row.
- S sits third to the right of Q.
- Either S or Q sits at an extreme end of the line.
- The one who faces Q sits second to the right of E.
- Two people sit between B and F.
- Neither B nor F sits at an extreme end of the line.
- The immediate neighbour of B faces the person who sits third to the left of P.
- R and T are immediate neighbours
- C sits second to the left of A
- T does not face the immediate neighbour of D.
Four of the following five are alike in a certain way based on the give arrangements and so form a group.Which is the one that does not belong to that group ?
From the first three conditions, two solns are possible
S _ _ Q _ _
_ E _ _ _ _
or
_ _ S _ _ Q
_ _ _ E _ _
As B and F have two people between them and neither are at the extremes, they must by in the second and fifth place. Hence, we can rule out configuration 1.
From the 6th condition, B should be fifth from left and F second.
Thus, we get
P _ S _ _ Q
_ F _ E B _
As C is second to the left of A, C must be first from left and A third. Hence, D is last from left. Thus, we can place all the people as follows
$$\downarrow$$ P V S T R Q
$$\uparrow$$ C F A E B D
In all pairs except E-Q, the first person faces an immediate neighbour of the second person.
Hence, option E is correct.
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