During Searle’s experiment, zero of the Vernier scale lies between $$3.20 \times 10^{−2} m$$ and $$3.25 \times 10^{-2} m$$ of the main scale. The $$20^{th}$$ division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between $$3.20 \times 10^{-2} m$$ and $$3.25 \times 10^{-2} m$$ of the main scale but now the $$45^{th}$$ division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is $$8 \times 10^{-7} m^2$$. The least count of the Vernier scale is $$1.0 \times 10^{-5} m$$. The maximum percentage error in the Young’s modulus of the wire is