A right circular cylindrical tank has the storage capacity of 98808 ml. If the radius of the base of the cylinder is three-fourth of the height, what is the diameter of the base ?
Volume if cylinder = π$$(R)^2$$h
R is the radius and h is the height of cylinder
Volume = 98808 ml
It is given that R = $$\frac{3}{4}$$h
$$\frac{4}{3}$$ $$(R)^3$$ π = 98808
R = 28.68
Diameter = 28.68 × 2 ~58
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