Question 116

The equation of the straight line passing through the point (2, 3) and perpendicular to the line x + 2y - 3 = 0 is


As per the given equation in the question,

$$\Rightarrow x + 2y - 3 = 0$$ the slope of the line $$m_1=\dfrac{-1}{2}$$

Let the slop of the required line is $$m_2$$.

When two lines are perpendicular to each other, then $$m_1\times m_2=-1$$

$$\Rightarrow m_2=\dfrac{-1}{\dfrac{-1}{2}}=2$$

We know the equation of line $$y=m_2 x+c$$

The above mentioned line is passing through the point (2,3)

So, $$3=4+c$$

$$\Rightarrow c=-1$$

Hence the equation of line $$y=2x-1$$

$$\Rightarrow 2x-y-1=0$$

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