Question 112

For any two statements p, q the statement $$\left(p \Rightarrow q \right) \vee \left(\sim \left(\left(\sim p\right) \Leftrightarrow q \right)\right)$$ is false only when

Solution

p	$$\rightsquigarrow$$q	$$\rightsquigarrow$$p$$\Rightarrow$$q	p⇒∼p	(p$$\rightsquigarrow$$q
T	F	T	F	F
F	T	F	T	F

From the above table, the truth value of the expression (∼p⇒p)∧(p⇒∼p) is always F. Hence it's a contradiction. so the p is always true and q is false Answer

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For any two statements p, q the statement $$\left(p \Rightarrow q \right) \vee \left(\sim \left(\left(\sim p\right) \Leftrightarrow q \right)\right)$$ is false only when

Solution

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