Study the given information carefully and answer the questions that follow:
An urn contains 3 red, 6 blue, 2 green and 4 yellow marbles.
If two marbles are picked at random, what is the probability that either both are red or both are green ?
Total number of marbles in the urn = 15
P(S) = Total possible outcomes
= Selecting 2 marbles at random out of 15
=> $$P(S) = C^{15}_2 = \frac{15 \times 14}{1 \times 2}$$
= $$105$$
P(E) = Favorable outcomes
= Selecting 2 green or 2 red marbles.
=> $$P(E) = C^2_2 + C^3_2$$
= $$1 + \frac{3 \times 2}{1 \times 2}$$
= $$4$$
$$\therefore$$ Required probability = $$\frac{P(E)}{P(S)}$$
= $$\frac{4}{105}$$
Create a FREE account and get: