Instructions

Study the given information carefully and answer the questions that follow:
An urn contains 6 red, 4 blue, 2 green, 3 yellow marbles.

Question 109

If four marbles are picked at random what is the probability that one is green two are blue and one is red ?

Solution

One green marble can be selected in $$^2C_1$$ = 2 ways.

Two blue marbles can be selected in $$^4C_2 = 6$$ ways

Six red marbles can be selected in $$^6C_1 = 6$$ ways.

Probability = $$\frac{2*6*6}{^{15}C_4}$$ = 24/455

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: