Question 108

Anitha walks a certain distance at (9/10)th of her usual speed and takes 27 minutes more than the usual time. Find the usual time taken. (in minutes)

Solution

Let usual speed = $$10$$ m/min and usual time taken = $$t$$ min

=> New speed = $$9$$ m/min and new time = $$(t+27)$$ min

Also, speed is inversely proportional to time.

=> $$\frac{10}{9}=\frac{t+27}{t}$$

=> $$10t=9t+243$$

=> $$10t-9t=t=243$$

$$\therefore$$ Usual time taken = 243 minutes

=> Ans - (A)

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