Question 104

A hallow iron pipe of 63 cms length having outer circumference of 440 cmis of thickness 4 cms. The volume(in cubic cms) of the iron used is ( Here take $$\pi = \frac{22}{7}$$)


Let the outer radius of pipe be R and inner radius be r. 

Also, we are given that 2*(22/7)*R = 440 cm ===> R = 70 cm 
Now, Volume of iron used in making the pipe = (22/7)*63*[(70*70)-(66*66)].......(as thickness is given as 4 cm)
Hence, Volume = 1,07,712 cubic cm

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