Question 102

If the area of an equilateral triangle is $$4\sqrt3$$ sq.cm.. then its perimeter, in centimetres, is

Solution

Let a is the length of the side of the equilateral triangle.

We know that the area of the equilateral triangle $$=\dfrac{\sqrt{3}a^2}{4}$$

So, $$\dfrac{\sqrt{3}a^2}{4}=4\sqrt3$$

$$a^2=4\times 4 $$

$$a=4$$

Hence, perimeter of the triangle $$=3a=12$$cm

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