Question 102
If the area of an equilateral triangle is $$4\sqrt3$$ sq.cm.. then its perimeter, in centimetres, is
Solution
Let a is the length of the side of the equilateral triangle.
We know that the area of the equilateral triangle $$=\dfrac{\sqrt{3}a^2}{4}$$
So, $$\dfrac{\sqrt{3}a^2}{4}=4\sqrt3$$
$$a^2=4\times 4 $$
$$a=4$$
Hence, perimeter of the triangle $$=3a=12$$cm
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