P’s workis twice as much as Q. If both work togetherthey finish a job in 12 days. If P works alone the number of days needed to complete that work?
Solution
Solution:
A/q
Let Q's efficiency be x%.
Then P's efficiency is 2x%
Total efficiency (if they work together) = (x + 2x)%= 3x %
With 3x% efficiency, time taken = 12 days.
So, with x% efficiency time taken = 13 x 3 = 36 days..... (Efficiency is indirectly proportional to Time taken)
So time taken if P works alone @ 2x % is = 36/2 days
= 18 days. Answer
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