A, B, C and D are four consecutive even numbers respectively and their average is 65. What is the product of A and D ?
As, A is the smallest even number of the four,
B = A+2
C = B+2 = A+4
D = C+2 = A+6
Hence, their sum is A + (A+2) + (A+4) + (A+6) = 4A + 12
And their average is (4A+12)/4 = A + 3
This equals 65.
So, A = 62 and D = A+6 = 68
Their product equals 62*68 = 4216
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