16 men by working 5 hours a day can complete a work in 15 days. 20 men by working 3 hours a day could complete one fourth of that work in $$x$$ days. If the working hours per day is fixed at 9 hours, and the number of men required to complete the remaining $$\frac{3}{4}$$ of the work in 4 days is y, then ($$x$$, y)=

A

(5, 15)

B

(8, 25)

C

(5, 25)

D

(8, 20)