Question 10

Four couples are to be seated in a circular table such that each couple sits together. In how many ways they can sit such that two males sit to the right of their female partners and the other two males sit to the left of their female partners ?

Solution

Two couples can be selected in $$^4C_2=6$$ ways.

The four couples can be seated in $$3!=6$$ ways.

Thus, the total ways of seating arrangement = $$6\times 6=36$$

Hence, the answer is option A.

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