Question 10
Four couples are to be seated in a circular table such that each couple sits together. In how many ways they can sit such that two males sit to the right of their female partners and the other two males sit to the left of their female partners ?
Solution
Two couples can be selected in $$^4C_2=6$$ ways.
The selected couples will have the males sitting to the left of the females, and the other couples will have it the other way around. In this way we cover all the possibilities of the conditions given.
The four couples can be seated in $$3!=6$$ ways.
Thus, the total ways of seating arrangement = $$6\times 6=36$$
Hence, the answer is option A.
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