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A plane progressive wave is given by $$y = 2\cos 2\pi(330t - x)$$ m. The frequency of the wave is :
Given $$y=2\cos 2\pi(330t-x)$$ m. The wave equation is $$y = A\cos(2\pi ft - 2\pi x/\lambda)$$. Comparing with $$y=2\cos 2\pi(330t-x)=2\cos(2\pi\cdot330\cdot t-2\pi x)$$, we get $$2\pi f = 2\pi \times 330 \implies f = 330$$ Hz.
The correct answer is Option (1): 330 Hz.
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