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Three forces $$F_1 = 10$$ N, $$F_2 = 8$$ N, $$F_3 = 6$$ N are acting on a particle of mass 5 kg. The forces $$F_2$$ and $$F_3$$ are applied perpendicularly so that particle remains at rest. If the force $$F_1$$ is removed, then the acceleration of the particle is
F₂ and F₃ are perpendicular. Their resultant = $$\sqrt{8^2 + 6^2} = \sqrt{100} = 10$$ N = F₁.
When F₁ is removed, the net force = resultant of F₂ and F₃ = 10 N.
$$a = F/m = 10/5 = 2$$ m/s²
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