Question 1

S and T can finish a work in 50 days. They worked together for 20 days and then left. How much of the work is left?

Solution

In 50 days 1 work completed by S and T

So, in 1 day $$\frac{1}{50}$$ work completed by S and T

In 20 days $$\frac{1}{50}\times\ 20=\frac{2}{5}$$ work completed by S and T

So left work = $$1-\frac{2}{5}=\frac{3}{5}$$.

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