Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Planck’s constant h
$$E=h\nu$$
$$[h]=\frac{[E]}{[\nu]}=\frac{ML^2T^{-2}}{T^{-1}}=[ML^2T^{-1}]$$
So, (A) matches with (III)
Stopping potential Vs:
Potential difference has dimensions:
$$[V]=\frac{\text{work}}{\text{charge}}=\frac{ML^2T^{-2}}{AT}=[ML^2T^{-3}A^{-1}]$$
So, (B) matches with (IV)
Work function $$\phi$$:
Work function is energy:
$$[\phi]=[ML^2T^{-2}]$$
So, (C) matches with (I)
Momentum p:
$$p=mv$$
$$[p]=M\cdot LT^{-1}=[MLT^{-1}]$$
So, (D) matches with (II)
Final matching:
(A)−(III), (B)−(IV), (C)−(I), (D)−(II)
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.