The pattern followed is that for $$a$$ $ $$b$$ = $$\frac{b}{a}$$

Eg = 5$125 = $$\frac{125}{5}=25$$

and 12$48 = $$\frac{48}{12}=4$$

Similarly, 4$24 = $$\frac{24}{4}=6$$

=> Ans - (C)

The pattern followed is that the sum of digits of second number is subtracted from the sum of digits of first number.

Eg : 45 % 11 = $$(4+5)-(1+1)=9-2=7$$

and 59 % 34 = $$(5+9)-(3+4)=14-7=7$$

Similarly, 55 % 4 = $$(5+5)-(4)=10-4=6$$

=> Ans - (A)

The pattern followed is that 10 is subtracted from the actual result.

Eg : $$(18\times12)-10=216-10=206$$

and $$(19\times22)-10=418-10=408$$

Similarly, $$(23\times36)-10=828-10=818$$

=> Ans - (B)

The pattern followed is that all the digits in the numbers are added.

Eg : 35 % 31 = $$3+5+3+1=12$$

and 92 % 30 = $$9+2+3+0=14$$

Similarly, 15 % 24 = $$1+5+2+4=12$$

=> Ans - (A)

The reform policies were first introduced in 1991 in India.

=> Ans - (C)

Expression : 6 + 8 ÷ 4 - 4 = 8

By interchanging :

(A) : ÷ and =

=> $$6+8=4-4\div8$$

L.H.S = $$14\neq$$ R.H.S. = $$3.5$$

(B) : ÷ and +

L.H.S. = $$6\div8+4-4$$

= $$3\div4=0.75\neq$$ R.H.S.

(C) : ÷ and -

L.H.S. = $$6+8-4\div4$$

= $$14-1=13\neq$$ R.H.S.

(D) : + and -

L.H.S. = $$6-8\div4+4$$

= $$6-2+4=8=$$ R.H.S.

=> Ans - (D)

Expression : 18 ? 6 ? 9 ? 27

(A) : x, ÷ and =

=> $$18\times6\div9=27$$

L.H.S. = $$2\times6=12\neq$$ R.H.S.

(B) : ÷, x and =

=> $$18\div6\times9=27$$

L.H.S. = $$3\times9=27=$$ R.H.S.

(C) : x, + and =

=> $$18\times6+9=27$$

L.H.S. = $$108+9=117\neq$$ R.H.S.

(D) : +, - and =

=> $$18+6-9=27$$

L.H.S. = $$24-9=15\neq$$ R.H.S.

=> Ans - (B)

Weights of 4 boxes = 20, 40, 50 and 30 kilograms

(A) : 140 = 20 + 30 + 40 + 50

(B) : 130 = not possible

(C) : 90 = 20 + 30 + 40

(D) : 120 = 30 + 40 + 50

=> Ans - (B)

The pattern is that the number in the middle is obtained by taking square of the difference of the numbers on each sides.

Eg : $$(19-13)^2=6^2=36$$

and $$(37-28)^2=9^2=81$$

Similarly, $$A=(43-38)^2=5^2=25$$

=> Ans - (B)

The pattern followed is that for $$a$$ $ $$b$$ = $$\frac{a+b}{2}$$

Eg : 11$25 = $$\frac{11+25}{2}=\frac{36}{2}=18$$

and 12$20 = $$\frac{12+20}{2}=\frac{32}{2}=16$$

Similarly, 4$50 = $$\frac{4+50}{2}=\frac{54}{2}=27$$

=> Ans - (C)

Weights of 4 boxes = 20, 90, 40 and 60 kilograms

(A) : 210 = 20 + 40 + 60 + 90

(B) : 170 = 20 + 60 + 90

(C) : 190 = 40 + 60 + 90

(D) : 200 = not possible

=> Ans - (D)

Weight of the boxes = 30, 20, 60 and 70 kilograms

(A) : 180 = 30 + 20 + 60 + 70 = 180

(B) : 150 = 20 + 60 + 70 = 150

(C) : 120 = 30 + 20 + 70 = 120

(D) : 170 = not possible

=> Ans - (D)

Weights of 4 boxes = 100, 70, 50 and 90 kilograms

(A) : 310 = 50 + 70 + 90 + 100

(B) : 260 = 70 + 90 + 100

(C) : 230 = not possible

(D) : 210 = 50 + 70 + 90

=> Ans - (C)

Gynecologists who are neither Women nor Dancers are represented by blue colour = C + H

=> Ans - (D)

Weights of 4 boxes = 30, 20, 50 and 90 kilograms

(A) : 200 = not possible

(B) : 190 = 20 + 30 + 50 + 90

(C) : 140 = 50 + 90

(D) : 160 = 20 + 50 + 90

=> Ans - (A)

Psychologists and actors who are also fathers are represented by blue area = E + G

=> Ans - (C)

Let the heights of these towers be represented by $$P,S,U,I,C$$ 

Pearl Towers is taller than Sky Towers but shorter than Unity Towers, => U > P > S

Unity Towers and Cyber Towers are of same height, => C = U > P > S

Pearl Towers is shorter than Indus Towers, => I is either the tallest or the second tallest building.

Thus, Pearl towers is the second shortest.

=> Ans - (A)

Expression : 8 x 3 ÷ 4 + 9 - 5 = 16

(A) : $$8\times4\div3+9-5=16$$

L.H.S. = $$10.67+4=14.67\neq$$ R.H.S.

(B) : $$4\times3\div8+9-5=16$$

L.H.S. = $$1.5+4=5.5\neq$$ R.H.S.

(C) : $$8\times5\div4+9-3=16$$

L.H.S. = $$10+6=16=$$ R.H.S.

(D) : $$8\times3\div4+5-9=16$$

L.H.S. = $$6-4=2\neq$$ R.H.S.

=> Ans - (C)

If yesterday was Tuesday, then today is = Wednesday

Also, 7th day from today is = Wednesday

Now, 10th day = Wednesday (+3) = Saturday

=> Ans - (D)

No painter is a man, thus painters who are either men or vegetarians are represented by blue region = E + B

=> Ans - (B)

Expression : 17- 15 x 5 = 250

(A) : = and x

 $$\equiv17-15=5\times250$$

L.H.S. $$=2\neq1250=$$ R.H.S.

(B) : x and -

$$\equiv17\times15-5=250$$

L.H.S. $$=255-5=250=$$ R.H.S.

=> Ans - (B)

The pattern followed is for $$a$$@$$b$$ = $$(a-b)\times2$$

Eg = 9@3 = $$(9-3)\times2=6\times2=12$$

and 15@4 = $$(15-4)\times2=11\times2=22$$

and 16@14 = $$(16-14)\times2=2\times2=4$$

Similarly, 6@2 = $$(6-2)\times2=4\times2=8$$

=> Ans - (D)

Manu's position from bottom end = 7th

=> Shreya's position from bottom end = 7 + 10 = 17th

Also, Shreya's position from top end = 8th

$$\therefore$$ Total number of people = (17+8) - 1 = 24

=> Ans - (C)

The pattern followed is that both the numbers are added and the result is multiplied by 2.

Eg : $$(26+14)\times2=40\times2=80$$

and $$(5+3)\times2=8\times2=16$$

and $$(6+5)\times2=11\times2=22$$

Similarly, $$(14+5)\times2=19\times2=38$$

=> Ans - (B)

If we add the numbers and take the square root, we get :

Eg : $$\sqrt{4+9+3}=\sqrt{16}=4$$

Also, $$\sqrt{5+3+1}=\sqrt{9}=3$$

Similarly, $$\sqrt{9+9+7}=\sqrt{25}=5$$

=> Ans - (A)

Total number of girls = 74

Shweta's position from left end = 27th

=> Palak's position from left end = 27 + 7 = 34th

Thus, Palak's position from right end = (74+1) - 34 = 41

=> Ans - (B)

Average temperature of a town in the first six days  = $$410C$$

=> Sum of temperatures in 6 days = $$6\times410=2460C$$

Sum of the temperatures of the first five days of the same month = $$2010C$$

$$\therefore$$ Temperature on the sixth day of the month = $$2460-2010=450C$$

=> Ans - (B)

Americans who are not accountants are represented by blue colour = G + H

=> Ans - (B)

It is given that all Mondays and Sundays are offs.

If a month starts with a Monday and has 31 days, then number of Mondays = 5 

But number of Sundays = 4

Thus, total off days = 4+5 = 9

=> Ans - (C)

It is given that C is in the extreme right. 

D is the immediate neighbour of A and E. B is at the right of E.

=> D sits to the immediate left of E, and A sits second to the left of E.

Thus, Arrangement :

$$\therefore$$ A is fourth to the left of C.

=> Ans - (D)

Khushboo's age = 25 years

=> Ankit's age = $$2\times25=50$$ years

=> Chandan's age = $$50+2=52$$ years

$$\therefore$$ Sumit's age = $$52+1=53$$ years

=> Ans - (B)

Surgeons are represented by = A+B+C+F+G

Mothers = A+F+H

Singers = C+D

Now, surgeons who are either mothers or singers = Surgeons $$\cap$$ (mothers $$\cup$$ singers)

= A,F,C

=> Ans - (B)

The pattern followed is that for $$a$$@$$b$$ = $$\frac{(a-b)}{2}$$

Eg : 17@1 = $$\frac{17-1}{2}=\frac{16}{2}=8$$

and 9@1 = $$\frac{9-1}{2}=\frac{8}{2}=4$$

and 6@4 = $$\frac{6-4}{2}=\frac{2}{2}=1$$

Similarly, 8@2 = $$\frac{8-2}{2}=\frac{6}{2}=3$$

=> Ans - (A)

The pattern followed is for $$a$$@$$b$$ = $$(a+b)\times10$$

Eg = 5@1 = $$(5+1)\times10=6\times10=60$$

and 12@8 = $$(12+8)\times10=20\times10=200$$

and 16@2 = $$(16+2)\times10=18\times10=180$$

Similarly, 16@10 = $$(16+10)\times10=26\times10=260$$

=> Ans - (D)

The pattern is that '@' is concatenate operator and '*' is used to add.

Eg : $$(3)^2 @ 1 * 7 = 9@1+7=91+7=98$$

and $$(4)^2 @ 2 * 16 = 16@2+16=162+16=178$$

Similarly, $$(5)^2 @ 3 * 9 = 25@3+9=253+9=262$$

=> Ans - (B)

Let A's present age = $$x$$ years

=> B's present age = $$(x-9)$$ years

According to ques,

=> $$(x+3)+(x-9-4)=76$$

=> $$2x-10=76$$

=> $$2x=76+10=86$$

=> $$x=\frac{86}{2}=43$$

Thus, B's present age = $$43-9 = 34$$

=> C's present age = $$\frac{34}{2}=17$$ years

$$\therefore$$ C's age after 10 years = $$17+10=27$$ years

=> Ans - (C)

The pattern followed is that sum of square of two rightmost numbers is subtracted from square of leftmost number.

Eg = $$9^2-(4^2+3^2)=81-16-9=56$$

and $$7^2-(2^2+1^2)=49-4-1=44$$

Similarly, $$11^2-(5^2+7^2)=121-25-49=47$$

=> Ans - (C)

Yoga practitioners who are neither geneticists nor fathers are represented by blue region = F + G

=> Ans - (D)

The pattern is that the number in the middle is obtained by multiplying the numbers on each sides and then dividing the result by '6'.

Eg : $$\frac{18\times3}{6}=3\times3=9$$

and $$\frac{36\times5}{6}=6\times5=30$$

Similarly, $$\frac{18\times19}{6}=3\times19=57$$

=> Ans - (B)

Total number of trees = 45

Position of lemon tree from right end = 20th

=> Rank of lemon tree from left end = $$(45+1)-20$$

= $$46-20=26$$

=> Ans - (A)

Total marks scored by Ankit in Physics, English and Philosophy respectively = $$32+45+49=126$$

Total aggregate marks of the three subjects = $$3\times50=150$$

$$\therefore$$ Required percentage = $$\frac{126}{150}\times100$$

= $$\frac{126}{3}\times2=84\%$$

=> Ans - (D)

Weights of 4 boxes = 40, 70, 80 and 50 kilograms

(A) : 240 = 40 + 50 + 70 + 80

(B) : 160 = 40 + 50 + 70

(C) : 200 = 50 + 70 + 80

(D) : 220 = not possible

=> Ans - (D)

C celebrated his fifth birthday 9 years ago, => C's present age = $$9 + 5 = 14$$ years

Also, after 8 years the B's age will be 4 times of C's present age, 

=> B's present age = $$(4\times14)-8=56-8=48$$ years

Thus, A's age = $$2\times48=96$$ years

=> Ans - (B)

Q's height is more than S and P but not more than R and S's height is more than P, 

=> R > Q > S > P

P's height is more than only one student, => T is the shortest.

$$\therefore$$ R > Q > S > P > T

Thus, R is the tallest in the class.

=> Ans - (B)

Expression : 8 x 9 + 2 = 74

(A) : x and =, 2 and 9

$$\equiv8=2+9\times74$$

R.H.S. $$=666+2=668\neq$$ L.H.S.

(B) : x and +, 8 and 2

$$\equiv2+9\times8=74$$

L.H.S. $$=2+72=74=$$ R.H.S.

=> Ans - (B)

Pooja is third to the extreme right end. Vishu is second to the left of Pooja. 

=> Vishu sits at extreme left end.

Vishakha is to the right of Pooja. Rani is third to the right of Ram, who is the immediate neighbour of Vishu.

=> Rani sits at extreme right end, and Ram sits between Vishu and Pooja.

Thus, arrangement :

$$\therefore$$ Pooja is sitting in the middle.

=> Ans - (A)

Let heights of Hitesh, Sunny, Vicky, Nitin and Bharat be represented as $$H,S,V,N,B$$ respectively.

Hitesh is at third place, => He is the third tallest and, =>  _ _ H _ _

Bharat is between Nitin and Hitesh while Nitin is not at the bottom, => N B H _ _ 

Thus, Nitin is the tallest among them.

=> Ans - (D)

Weights of 4 boxes = 70, 50, 30 and 90 kilograms

(A) : 220 = not possible

(B) : 240 = 30 + 50 + 70 + 90

(C) : 210 = 50 + 70 + 90

(D) : 170 = 30 + 50 + 90

=> Ans - (A)

Weights of 4 boxes = 20, 40, 80 and 90 kilograms

(A) : 220 = not possible

(B) : 230 = 20 + 40 + 80 + 90

(C) : 150 = 20 + 40 + 90

(D) : 210 = 40 + 80 + 90

=> Ans - (A)

Bottles that are not brown are represented by blue colour = 31 + 26 + 1 = 58

=> Ans - (A)