Free solved questions in SSC CGL Reasoning for SSC with answers and solutions

Instructions

For the following questions answer them individually

Question 1

If 45 % 11 = 7, 59 % 34 = 7 then what is the value of 55 % 4 = ?

Solution

The pattern followed is that the sum of digits of second number is subtracted from the sum of digits of first number.

Eg : 45 % 11 = $$(4+5)-(1+1)=9-2=7$$

and 59 % 34 = $$(5+9)-(3+4)=14-7=7$$

Similarly, 55 % 4 = $$(5+5)-(4)=10-4=6$$

=> Ans - (A)

Question 2

In the following figure, square represents Pharmacists, triangle represents Dancers, circle represents Gynecologists and rectangle represents Women. Which set of letters represents Gynecologists who are neither Women nor Dancers?

Solution

Gynecologists who are neither Women nor Dancers are represented by blue colour = C + H

=> Ans - (D)

Question 3

The weights of 4 boxes are 30, 20, 50 and 90 kilograms. Which of the following cannot be the total weight, in kilograms, of any combination of these boxes and in a combination a box can be used only once?

Solution

Weights of 4 boxes = 30, 20, 50 and 90 kilograms

(A) : 200 = not possible

(B) : 190 = 20 + 30 + 50 + 90

(C) : 140 = 50 + 90

(D) : 160 = 20 + 50 + 90

=> Ans - (A)

Question 4

In the following figure, square represents Psychologists, triangle represents Chemists, circle represents Actors and rectangle represents Fathers. Which set of letters represents Psychologists and actors who are also fathers?

Solution

Psychologists and actors who are also fathers are represented by blue area = E + G

=> Ans - (C)

Question 5

Pearl Towers is taller than Sky Towers but shorter than Unity Towers. Unity Towers and Cyber Towers are of same height. Pearl Towers is shorter than Indus Towers. Amongst the buildings, who is the second shortest?

Solution

Let the heights of these towers be represented by $$P,S,U,I,C$$

Pearl Towers is taller than Sky Towers but shorter than Unity Towers, => U > P > S

Unity Towers and Cyber Towers are of same height, => C = U > P > S

Pearl Towers is shorter than Indus Towers, => I is either the tallest or the second tallest building.

Thus, Pearl towers is the second shortest.

=> Ans - (A)

Question 6

In India the reform policies were first introduced in which year?

Solution

The reform policies were first introduced in 1991 in India.

=> Ans - (C)

Question 7

In the following question, correct the equation by interchanging two signs.
6 + 8 ÷ 4 - 4 = 8

Solution

Expression : 6 + 8 ÷ 4 - 4 = 8

By interchanging :

(A) : ÷ and =

=> $$6+8=4-4\div8$$

L.H.S = $$14\neq$$ R.H.S. = $$3.5$$

(B) : ÷ and +

L.H.S. = $$6\div8+4-4$$

= $$3\div4=0.75\neq$$ R.H.S.

(C) : ÷ and -

L.H.S. = $$6+8-4\div4$$

= $$14-1=13\neq$$ R.H.S.

(D) : + and -

L.H.S. = $$6-8\div4+4$$

= $$6-2+4=8=$$ R.H.S.

=> Ans - (D)

Question 8

In the following question, by using which mathematical operator will the expression become correct?

18 ? 6 ? 9 ? 27

Solution

Expression : 18 ? 6 ? 9 ? 27

(A) : x, ÷ and =

=> $$18\times6\div9=27$$

L.H.S. = $$2\times6=12\neq$$ R.H.S.

(B) : ÷, x and =

=> $$18\div6\times9=27$$

L.H.S. = $$3\times9=27=$$ R.H.S.

(C) : x, + and =

=> $$18\times6+9=27$$

L.H.S. = $$108+9=117\neq$$ R.H.S.

(D) : +, - and =

=> $$18+6-9=27$$

L.H.S. = $$24-9=15\neq$$ R.H.S.

=> Ans - (B)

Question 9

The weights of 4 boxes are 20, 40, 50 and 30 kilograms. Which of the following cannot be the total weight, in kilograms, of any combination of these boxes and in a combination a box can be used only once

Solution

Weights of 4 boxes = 20, 40, 50 and 30 kilograms

(A) : 140 = 20 + 30 + 40 + 50

(B) : 130 = not possible

(C) : 90 = 20 + 30 + 40

(D) : 120 = 30 + 40 + 50

=> Ans - (B)

Question 10

If 19 (36) 13 and 37 (81) 28, then what is the value of 'A' in 43 (A) 38?

Solution

The pattern is that the number in the middle is obtained by taking square of the difference of the numbers on each sides.

Eg : $$(19-13)^2=6^2=36$$

and $$(37-28)^2=9^2=81$$

Similarly, $$A=(43-38)^2=5^2=25$$

=> Ans - (B)

Question 11

The weights of 4 boxes are 20, 90, 40 and 60 kilograms. Which of the following cannot be the total weight,in kilograms, of any combination of these boxes and in a combination a box can be used only once?

Solution

Weights of 4 boxes = 20, 90, 40 and 60 kilograms

(A) : 210 = 20 + 40 + 60 + 90

(B) : 170 = 20 + 60 + 90

(C) : 190 = 40 + 60 + 90

(D) : 200 = not possible

=> Ans - (D)

Question 12

The weights of 4 boxes are 100, 70, 50 and 90 kilograms. Which of the following cannot be the total weight, in kilograms, of any combination of these boxes and in a combination a box can be used only once?

Solution

Weights of 4 boxes = 100, 70, 50 and 90 kilograms

(A) : 310 = 50 + 70 + 90 + 100

(B) : 260 = 70 + 90 + 100

(C) : 230 = not possible

(D) : 210 = 50 + 70 + 90

=> Ans - (C)

Question 13

In the following question, correct the given equation by interchanging two numbers.

8 x 3 ÷ 4 + 9 - 5 = 16

Solution

Expression : 8 x 3 ÷ 4 + 9 - 5 = 16

(A) : $$8\times4\div3+9-5=16$$

L.H.S. = $$10.67+4=14.67\neq$$ R.H.S.

(B) : $$4\times3\div8+9-5=16$$

L.H.S. = $$1.5+4=5.5\neq$$ R.H.S.

(C) : $$8\times5\div4+9-3=16$$

L.H.S. = $$10+6=16=$$ R.H.S.

(D) : $$8\times3\div4+5-9=16$$

L.H.S. = $$6-4=2\neq$$ R.H.S.

=> Ans - (C)

Question 14

In the following figure, square represents Optometrists, triangle represents Painters, circle represents Vegetarians and rectangle represents Men. Which set of letters represents painters who are either men or vegetarians?

Solution

No painter is a man, thus painters who are either men or vegetarians are represented by blue region = E + B

=> Ans - (B)

Question 15

If 9@3=12; 15@4=22; 16@14=4; then what is the value of 6@2=?

Solution

The pattern followed is for $$a$$@$$b$$ = $$(a-b)\times2$$

Eg = 9@3 = $$(9-3)\times2=6\times2=12$$

and 15@4 = $$(15-4)\times2=11\times2=22$$

and 16@14 = $$(16-14)\times2=2\times2=4$$

Similarly, 6@2 = $$(6-2)\times2=4\times2=8$$

=> Ans - (D)

Question 16

In a row of 74 girls, Shweta is 27th from left end. Palak is 7th to the right of Shweta. What is Palak's position from the right end of the row?

Solution

Total number of girls = 74

Shweta's position from left end = 27th

=> Palak's position from left end = 27 + 7 = 34th

Thus, Palak's position from right end = (74+1) - 34 = 41

=> Ans - (B)

Question 17

In the following figure, square represents Painters, triangle represents women, circle represents Accountants and rectangle represents Americans. Which set of letters represents Americans who are not accountants?

Solution

Americans who are not accountants are represented by blue colour = G + H

=> Ans - (B)

Question 18

If 17@1=8; 9@1=4; 6@4=1; then what is the value of 8@2=?

Solution

The pattern followed is that for $$a$$@$$b$$ = $$\frac{(a-b)}{2}$$

Eg : 17@1 = $$\frac{17-1}{2}=\frac{16}{2}=8$$

and 9@1 = $$\frac{9-1}{2}=\frac{8}{2}=4$$

and 6@4 = $$\frac{6-4}{2}=\frac{2}{2}=1$$

Similarly, 8@2 = $$\frac{8-2}{2}=\frac{6}{2}=3$$

=> Ans - (A)

Question 19

In the following figure, square represents Pharmacists, triangle represents singers, circle represents Surgeons and rectangle represents Mothers. Which set of letters represents surgeons who are either mothers or singers?

Solution

Surgeons are represented by = A+B+C+F+G

Mothers = A+F+H

Singers = C+D

Now, surgeons who are either mothers or singers = Surgeons $$\cap$$ (mothers $$\cup$$ singers)

= A,F,C

=> Ans - (B)

Question 20

If 5@1=60; 12@8=200; 16@2=180; then what is the value of 16@10=?

Solution

The pattern followed is for $$a$$@$$b$$ = $$(a+b)\times10$$

Eg = 5@1 = $$(5+1)\times10=6\times10=60$$

and 12@8 = $$(12+8)\times10=20\times10=200$$

and 16@2 = $$(16+2)\times10=18\times10=180$$

Similarly, 16@10 = $$(16+10)\times10=26\times10=260$$

=> Ans - (D)

Question 21

If $$(3)^2 @ 1 * 7 = 98$$ and $$(4)^2 @ 2 * 16 = 178$$, then $$(5)^2 @ 3 * 9 = ?$$

Solution

The pattern is that '@' is concatenate operator and '*' is used to add.

Eg : $$(3)^2 @ 1 * 7 = 9@1+7=91+7=98$$

and $$(4)^2 @ 2 * 16 = 16@2+16=162+16=178$$

Similarly, $$(5)^2 @ 3 * 9 = 25@3+9=253+9=262$$

=> Ans - (B)

Question 22

Nine years later, age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago is 76. If C is half of the present age of B, then what will be C's age (in years) after 10 years?

Solution

Let A's present age = $$x$$ years

=> B's present age = $$(x-9)$$ years

According to ques,

=> $$(x+3)+(x-9-4)=76$$

=> $$2x-10=76$$

=> $$2x=76+10=86$$

=> $$x=\frac{86}{2}=43$$

Thus, B's present age = $$43-9 = 34$$

=> C's present age = $$\frac{34}{2}=17$$ years

$$\therefore$$ C's age after 10 years = $$17+10=27$$ years

=> Ans - (C)

Question 23

If $$9^{2}$$ A $$4^{2}$$ B $$3^{2}$$ = 56 and $$7^{2}$$ A $$2^{2}$$ B $$1^{2}$$ = 44, then

$$11^{2}$$ A $$5^{2}$$ B $$7^{2}$$ = ?

Solution

The pattern followed is that sum of square of two rightmost numbers is subtracted from square of leftmost number.

Eg = $$9^2-(4^2+3^2)=81-16-9=56$$

and $$7^2-(2^2+1^2)=49-4-1=44$$

Similarly, $$11^2-(5^2+7^2)=121-25-49=47$$

=> Ans - (C)

Question 24

In the following figure, square represents Therapists, triangle represents Geneticists, circle represents yoga practitioners and rectangle represents Fathers. Which set of letters represents yoga practitioners who are neither geneticists nor fathers?

Solution

Yoga practitioners who are neither geneticists nor fathers are represented by blue region = F + G

=> Ans - (D)

Question 25

If 18 (9) 3 and 36 (30) 5, then what is the value of A in 19 (A) 18?

Solution

The pattern is that the number in the middle is obtained by multiplying the numbers on each sides and then dividing the result by '6'.

Eg : $$\frac{18\times3}{6}=3\times3=9$$

and $$\frac{36\times5}{6}=6\times5=30$$

Similarly, $$\frac{18\times19}{6}=3\times19=57$$

=> Ans - (B)

Question 26

There are 45 trees in a row. The lemon tree is 20th from right end. What is the rank of lemon tree from left end?

Solution

Total number of trees = 45

Position of lemon tree from right end = 20th

=> Rank of lemon tree from left end = $$(45+1)-20$$

= $$46-20=26$$

=> Ans - (A)

Question 27

The weights of 4 boxes are 40, 70, 80 and 50 kilograms.Which of the following cannot be the total weight,in kilograms, of any combination of these boxes and in a combination a box can be used only once

Solution

Weights of 4 boxes = 40, 70, 80 and 50 kilograms

(A) : 240 = 40 + 50 + 70 + 80

(B) : 160 = 40 + 50 + 70

(C) : 200 = 50 + 70 + 80

(D) : 220 = not possible

=> Ans - (D)

Question 28

Present age of A is 2 times the present age of B. After 8 years the B's age will be 4 times of C's present age. If C celebrated his fifth birthday 9 years
ago, then what is the present age (in years) of A?

Solution

C celebrated his fifth birthday 9 years ago, => C's present age = $$9 + 5 = 14$$ years

Also, after 8 years the B's age will be 4 times of C's present age,

=> B's present age = $$(4\times14)-8=56-8=48$$ years

Thus, A's age = $$2\times48=96$$ years

=> Ans - (B)

Question 29

There are five students - P, Q, R, S and T having different heights in a class. P's height is more than only one student. Q's height is more than S and P but not more than R. S's height is more than P. R is not the smallest. Who is having the maximum height in the class?

Solution

Q's height is more than S and P but not more than R and S's height is more than P,

=> R > Q > S > P

P's height is more than only one student, => T is the shortest.

$$\therefore$$ R > Q > S > P > T

Thus, R is the tallest in the class.

=> Ans - (B)

Question 30

Hitesh, Sunny, Vicky, Nitin and Bharat are arranged in ascending order of the height from the top. Hitesh is at third place. Bharat is between Nitin and Hitesh while Nitin is not at the bottom. Who has the maximum height among them?

Solution

Let heights of Hitesh, Sunny, Vicky, Nitin and Bharat be represented as $$H,S,V,N,B$$ respectively.

Hitesh is at third place, => He is the third tallest and, => _ _ H _ _

Bharat is between Nitin and Hitesh while Nitin is not at the bottom, => N B H _ _

Thus, Nitin is the tallest among them.

=> Ans - (D)

Question 31

The weights of 4 boxes are 70, 50, 30 and 90 kilograms. Which of the following cannot be the total weight,in kilograms, of any combination of these boxes and in a combination a box can be used only once

Solution

Weights of 4 boxes = 70, 50, 30 and 90 kilograms

(A) : 220 = not possible

(B) : 240 = 30 + 50 + 70 + 90

(C) : 210 = 50 + 70 + 90

(D) : 170 = 30 + 50 + 90

=> Ans - (A)

Question 32

If 35 % 31 = 12, 92 % 30 = 14 then what is the value of 15 % 24 = ?

Solution

The pattern followed is that all the digits in the numbers are added.

Eg : 35 % 31 = $$3+5+3+1=12$$

and 92 % 30 = $$9+2+3+0=14$$

Similarly, 15 % 24 = $$1+5+2+4=12$$

=> Ans - (A)

Question 33

If 18 x 12 = 206 and 19 x 22 = 408, then

23 x 36 = ?

Solution

The pattern followed is that 10 is subtracted from the actual result.

Eg : $$(18\times12)-10=216-10=206$$

and $$(19\times22)-10=418-10=408$$

Similarly, $$(23\times36)-10=828-10=818$$

=> Ans - (B)

Question 34

In the given figure , how many bottles are not brown

Solution

Bottles that are not brown are represented by blue colour = 31 + 26 + 1 = 58

=> Ans - (A)

Question 35

If 5$125 = 25, 12$48 = 4 then what is the value of 4$24 = ?

Solution

The pattern followed is that for $$a$$ $ $$b$$ = $$\frac{b}{a}$$

Eg = 5$125 = $$\frac{125}{5}=25$$

and 12$48 = $$\frac{48}{12}=4$$

Similarly, 4$24 = $$\frac{24}{4}=6$$

=> Ans - (C)

Question 36

If 11$25 = 18, 12$20 = 16 then what is the value of 4$50 = ?

Solution

The pattern followed is that for $$a$$ $ $$b$$ = $$\frac{a+b}{2}$$

Eg : 11$25 = $$\frac{11+25}{2}=\frac{36}{2}=18$$

and 12$20 = $$\frac{12+20}{2}=\frac{32}{2}=16$$

Similarly, 4$50 = $$\frac{4+50}{2}=\frac{54}{2}=27$$

=> Ans - (C)

Question 37

The weights of 4 boxes are 30, 20, 60 and 70 kilograms. Which of the following cannot be the total weight,in kilograms, of any combination of these boxes and in a combination a box can be used only once?

Solution

Weight of the boxes = 30, 20, 60 and 70 kilograms

(A) : 180 = 30 + 20 + 60 + 70 = 180

(B) : 150 = 20 + 60 + 70 = 150

(C) : 120 = 30 + 20 + 70 = 120

(D) : 170 = not possible

=> Ans - (D)

Question 38

If yesterday was Tuesday, then what day of the week will the tenth day from today be?

Solution

If yesterday was Tuesday, then today is = Wednesday

Also, 7th day from today is = Wednesday

Now, 10th day = Wednesday (+3) = Saturday

=> Ans - (D)

Question 39

Which of the following interchanges in signs will make the given equation correct?
17- 15 x 5 = 250

Solution

Expression : 17- 15 x 5 = 250

(A) : = and x

$$\equiv17-15=5\times250$$

L.H.S. $$=2\neq1250=$$ R.H.S.

(B) : x and -

$$\equiv17\times15-5=250$$

L.H.S. $$=255-5=250=$$ R.H.S.

=> Ans - (B)

Question 40

In a row of people Manu is 7th from bottom end of row. Shrey is 10 ranks above Manu. If Shrey is 8th from top end, then how many people are there in this row?

Solution

Manu's position from bottom end = 7th

=> Shreya's position from bottom end = 7 + 10 = 17th

Also, Shreya's position from top end = 8th

$$\therefore$$ Total number of people = (17+8) - 1 = 24

=> Ans - (C)

Question 41

If 26#14=80; 5#3=16; 6#5=22; then what is the value of 14#5=?

Solution

The pattern followed is that both the numbers are added and the result is multiplied by 2.

Eg : $$(26+14)\times2=40\times2=80$$

and $$(5+3)\times2=8\times2=16$$

and $$(6+5)\times2=11\times2=22$$

Similarly, $$(14+5)\times2=19\times2=38$$

=> Ans - (B)

Question 42

If 4 x 9 x 3 = 4 and 5 x 3 x 1 = 3, then 9 x 9 x 7 = ?

Solution

If we add the numbers and take the square root, we get :

Eg : $$\sqrt{4+9+3}=\sqrt{16}=4$$

Also, $$\sqrt{5+3+1}=\sqrt{9}=3$$

Similarly, $$\sqrt{9+9+7}=\sqrt{25}=5$$

=> Ans - (A)

Question 43

The average temperature of a town in the ﬁrst six days of a month was 410C and the sum of the temperatures of the ﬁrst ﬁve days of the same month was 2010C. What was the temperature on the sixth day of the month?

Solution

Average temperature of a town in the ﬁrst six days = $$410C$$

=> Sum of temperatures in 6 days = $$6\times410=2460C$$

Sum of the temperatures of the ﬁrst ﬁve days of the same month = $$2010C$$

$$\therefore$$ Temperature on the sixth day of the month = $$2460-2010=450C$$

=> Ans - (B)

Question 44

In a company all Mondays and Sundays are offs. If a month starts with a Monday and has 31 days then how many offs will be there in that month?

Solution

It is given that all Mondays and Sundays are offs.

If a month starts with a Monday and has 31 days, then number of Mondays = 5

But number of Sundays = 4

Thus, total off days = 4+5 = 9

=> Ans - (C)

Question 45

A, B, C,D and E are standing in a row. D is the immediate neighbour of A and E. B is at the right of E and C is in the extreme right. Who is fourth to the left of C?

Solution

It is given that C is in the extreme right.

D is the immediate neighbour of A and E. B is at the right of E.

=> D sits to the immediate left of E, and A sits second to the left of E.

Thus, Arrangement :

$$\therefore$$ A is fourth to the left of C.

=> Ans - (D)

Question 46

Chandan is 2 years older than Ankit but 1 year younger than Sumit. Ankit is twice as old as Khushboo. If Khushboo's age is 25 years, what is the age (in years) of Sumit?

Solution

Khushboo's age = 25 years

=> Ankit's age = $$2\times25=50$$ years

=> Chandan's age = $$50+2=52$$ years

$$\therefore$$ Sumit's age = $$52+1=53$$ years

=> Ans - (B)

Question 47

Ankit scored 32, 45 and 49 marks in Physics, English and Philosophy respectively. The maximum marks in each subject is 50. Determine his overall percentage for the three subjects.

Solution

Total marks scored by Ankit in Physics, English and Philosophy respectively = $$32+45+49=126$$

Total aggregate marks of the three subjects = $$3\times50=150$$

$$\therefore$$ Required percentage = $$\frac{126}{150}\times100$$

= $$\frac{126}{3}\times2=84\%$$

=> Ans - (D)

Question 48

Which of the following interchanges in signs and numbers will make the given equation correct?
8 x 9 + 2 = 74

Solution

Expression : 8 x 9 + 2 = 74

(A) : x and =, 2 and 9

$$\equiv8=2+9\times74$$

R.H.S. $$=666+2=668\neq$$ L.H.S.

(B) : x and +, 8 and 2

$$\equiv2+9\times8=74$$

L.H.S. $$=2+72=74=$$ R.H.S.

=> Ans - (B)

Question 49

Vishu,Pooja,Vishakha,Rani and Ram are sitting in a line. Pooja is third to the extreme right end. Vishu is second to the left of Pooja. Vishakha is to the right of Pooja. Rani is third to the right of Ram, who is the immediate neighbour of Vishu. Who is sitting in the middle?

Solution

Pooja is third to the extreme right end. Vishu is second to the left of Pooja.

=> Vishu sits at extreme left end.

Vishakha is to the right of Pooja. Rani is third to the right of Ram, who is the immediate neighbour of Vishu.

=> Rani sits at extreme right end, and Ram sits between Vishu and Pooja.

Thus, arrangement :

$$\therefore$$ Pooja is sitting in the middle.

=> Ans - (A)

Question 50

The weights of 4 boxes are 20, 40, 80 and 90 kilograms. Which of the following cannot be the total weight, in kilograms, of any combination of these boxes and in a combination a box can be used only once?

Solution

Weights of 4 boxes = 20, 40, 80 and 90 kilograms

(A) : 220 = not possible

(B) : 230 = 20 + 40 + 80 + 90

(C) : 150 = 20 + 40 + 90

(D) : 210 = 40 + 80 + 90

=> Ans - (A)

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