SSC CHSL 3 July 2019 Shift-2

Instructions

For the following questions answer them individually

Question 51

If $$x + \frac{1}{x} = 7,  then  x^3 + \frac{1}{x^3}$$ is equal to:

Video Solution
Question 52

Two numbers A and arein the ratio 5 : 2, If 4 is added to each number then this ratio becomes 9 : 4. If 5 is subtracted from each ofthe original numbers,then the ratio of A and B will be:

Video Solution
Question 53

The given Bar Graph presents the number of students enrolled for a vocational course in institutes A and B during a period of five years.

What is the ratio of the total numbers of students enrolled in A during 2015 and 2018 to that of students enrolled in B during 2014 and 2016?

Video Solution

Question 54

If x ≠ -1, 2 and 5, then the simplified value of 

$$\left\{\frac{2(x^3 - 8)}{x^2 -x -2} \times \frac{x^2 + 2x +1}{x^2 - 4x - 5} \div \frac{x^2 + 2x + 4}{3x - 15}\right\}$$ is equal to:

Video Solution
Question 55

A certain sum amounts to ₹29282 in 4 years at 10% per annum, when the interest is compounded annually. What is the simple interest on the same sum for same timeat the same rate ?

Video Solution
Question 56

In $$\triangle$$ABC, AD,the bisector of $$\angle$$A, meets BC at D. If BC = a, AC = b and AB =c, then BD - DC =

Video Solution

Question 57

A wire is in the shape of a rectangle whose sides are in the ratio 7 : 4. It was initially in the shape of a circle of radius, very nearly equal to 31.5 cm. The length of smaller side of the rectangle is:(Take $$\pi = \frac{22}{7}$$)

Video Solution
Question 58

A and B together can do a piece of work in 10 days, B and C together can doit in 15 days while C and A together can do it in 20 days. They work together for 8 days. C alone will complete the remaining work in:

Video Solution
Question 59

A rectangle ABCD is inscribed in a circle with centre O.Its diagonal CA is produced to a point E, outside the circle. ED is a tangent to the circle at D. If AC = 2BC,then what is the measure of $$\angle$$DEC ?

Video Solution

Question 60

Let $$\triangle ABC \sim \triangle QPR  and  \frac{ar(\triangle ABC)}{ar(\triangle PQR)} = \frac{9}{16}$$. If AB = 12 cm, BC = 6 cm and AC = 9 cm,then QR is equal to:

Video Solution
cracku

Boost your Prep!

Download App