SSC CGL Tier l 2023 Question Paper Shift 2 (July 27th)

Instructions

For the following questions answer them individually

SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 61


Angle subtended by the largest chord of the circle to a point on the same circle measures:

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 62


Simplify the given expression.
$$\frac{\left[120 \times 120 \times 120 - 100 \times 100 \times 100\right]}{\left[120 \times 120 + 120 \times 100 + 100 \times 100\right]}$$

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 63


A, B and C can do a piece of work in 20, 30 and 60 days, respectively. In how many days can A do the work if he is assisted by both B and C on every third day?

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 64


Soham’s initial expenditure and savings were in the ratio of 5 : 3. His income increases by 25%. If his initial savings were ₹4,500, find his income (in ₹) after the increment.

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 65


If $$\left(a + b + c\right) = 14$$, and $$\left(a^{3} + b^{3} + c^{3} - 3abc\right) = 98$$, find the value of $$\left(a^{2} + b^{2} + c^{2}\right)$$.

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 66


ABC is a triangle and D is a point on the side BC. If BC = 16 cm, BD = 11 cm and $$\angle ADC = \angle BAC$$, then the length of AC is equal to:

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 67


A 6-digit number has digits as consecutive natural numbers. The number is always divisible by ___________.

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 68


Benny can do a piece of work in 24 days. Chethan and David can do the same work individually in 36 and 48 days, respectively. All of them begin the work together. However, Benny leaves the work 4 days before the completion of work and Chethan leaves the work 10 days before the completion of the work. David worked till the end and completed the work. Find the number of days in which the work was completed.

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 69


A thief robs precious metals from a store which is 1150 m away from the police. The thief starts running at 6 km/h and the police starts chasing at 11 km/h at the same time. How much distance (in m) will the thief run before being caught?

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SSC CGL Tier l 2023 Shift 2 (July 27th) - Question 70


The value of $$1\frac{3}{4} + 1\frac{5}{7} \div 2\frac{3}{7} \times 2\frac{3}{7}$$ = ?

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