SSC CGL Tier l 2023 Question Paper Shift 1 (July 27th)

Instructions

For the following questions answer them individually

SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 61


The following data shows the number of boys and girls in Class VII, Class VIII, Class IX and Class X of a school. Study the data and answer the question.

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Which class has the maximum number of students?

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 62


Ashok and Anil undertake to do a piece of work for ₹4,500. Ashok alone could do the work in the 8 days and Anil in 12 days. With the assistance of Amar, they finished the work in 4 days. What is the share of Amar?

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 63


In the figure, AB = AD = 9 cm and AC = AE = 13 cm and BC = 15 cm. Find ED?

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 64


Given $$\theta_1 + \theta_2 = \frac{\pi}{2}$$ and $$\theta_1 = \frac{1}{2}$$, find the value of $$\theta_2$$.

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 65


Find the simple interest on ₹27,000 at $$14\frac{2}{3}\%$$ per annum for 8 months.

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 66


Find the value.
$$80.40 \div 20 - (-4.02) + 2.06 =$$ __________

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 67


What is the value of given expression if $$3 \cot A = \frac{7}{3}$$?
$$\frac{3 \cos A + 2 \sin A}{3 \cos A - 2 \sin A}$$

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 68


A man, a woman and a boy can complete a job in 3, 5 and 15 days, respectively. How many boys must assist 1 man and 1 woman to complete the job in $$\frac{1}{5}$$ of a day?

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 69


A shopkeeper gives a 12% additional discount on the discounted price, after giving an initial discount of 25% on the labelled price of a radio. If the final selling price of the radio is ₹792, then what is its labelled price (in ₹)?

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SSC CGL Tier l 2023 Shift 1 (July 27th) - Question 70


Which of the following is the smallest ratio?
$$\frac{5}{6}, \frac{7}{9}, \frac{11}{12}, \frac{13}{18}$$

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