NTA JEE Mains 9th April 2024 Shift 2

A proton and a deutron ($$q = +e, m = 2.0u$$) having same kinetic energies enter a region of uniform magnetic field $$\vec{B}$$, moving perpendicular to $$\vec{B}$$. The ratio of the radius of deutron path to the radius of the proton path is:

A square loop of side $$15 \text{ cm}$$ being moved towards right at a constant speed of $$2 \text{ cm/s}$$ as shown in figure. The front edge enters the $$50 \text{ cm}$$ wide magnetic field at $$t = 0$$. The value of induced emf in the loop at $$t = 10 \text{ s}$$ will be :

The magnetic field in a plane electromagnetic wave is $$B_y = (3.5 \times 10^{-7}) \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \text{ T}$$. The corresponding electric field will be :

The following figure represents two biconvex lenses $$L_1$$ and $$L_2$$ having focal length $$10 \text{ cm}$$ and $$15 \text{ cm}$$ respectively. The distance between $$L_1$$ & $$L_2$$ is 

UV light of $$4.13 \text{ eV}$$ is incident on a photosensitive metal surface having work function $$3.13 \text{ eV}$$. The maximum kinetic energy of ejected photoelectrons will be:

A hydrogen atom in ground state is given an energy of $$10.2 \text{ eV}$$. How many spectral lines will be emitted due to transition of electrons?

A nucleus at rest disintegrates into two smaller nuclei with their masses in the ratio of $$2 : 1$$. After disintegration they will move :

The energy released in the fusion of $$2 \text{ kg}$$ of hydrogen deep in the sun is $$E_H$$ and the energy released in the fission of $$2 \text{ kg}$$ of $$^{235}U$$ is $$E_U$$. The ratio $$\frac{E_H}{E_U}$$ is approximately: (Consider the fusion reaction as $$4 \mid H + 2e^- \to {}^4_2He + 2\nu + 6\gamma + 26.7 \text{ MeV}$$, energy released in the fission reaction of $$^{235}U$$ is $$200 \text{ MeV}$$ per fission nucleus and $$N_A = 6.023 \times 10^{23}$$)

The $$I - V$$ characteristics of an electronic device shown in the figure. The device is:

In the truth table of the above circuit the value of $$X$$ and $$Y$$ are :